Archive for November, 2010

Before you say anything, this has nothing to do with homework

I think I’ve got a good formula for figuring it out, but I just want to run it by anyone else into H0 scale model railroading.

If it took 3 curves to make a 90 degree turn then each piece would be 30 degrees.

If it took 4 curves to make a 90 degree turn then each piece would be 22.5 degrees.

So count the number of pieces it takes to make a 90 degree curve

Divide 90 by the number of track pieces needed

90 degrees / 3 curves = 30 degrees each curve

90 degrees / 4 curves = 22.5 degrees each curve

To make sure it is correct, you times the number of curves by the amount of degrees of each piece, and if the answer is 90, then it is right.

Formula:
X = degrees
Y = per track piece
Z = Track pieces

90X / # of Z needed to make 90X = # of XY
# of Z needed to make 90X x # of XY = 90X

Example:
90 / 3 = 30
3 x 30 = 90

90 / 4 = 22.5
4 x 22.5 = 90

Would this formula be suitable to figure out the circumference of each track piece as long as each curve track used is the same?


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